\(x=\sqrt3+\sqrt2\) হলে \((x^3+\cfrac{1}{x^3})\) এর সরলতম মান নির্ণয় করো।
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\(x=\sqrt3+\sqrt2\)
বা, \(\cfrac{1}{x}=\cfrac{1}{\sqrt3+\sqrt2}\)
\(=\cfrac{(\sqrt3-\sqrt2)}{(\sqrt3+\sqrt2)(\sqrt3-\sqrt2)}\)
\(=\cfrac{(\sqrt3-\sqrt2)}{3-2}\)
\(=\sqrt3-\sqrt2\)
\(\therefore x-\cfrac{1}{x}=\sqrt3+\sqrt2+\sqrt3-\sqrt2=2\sqrt3\)
\(x^3+\cfrac{1}{x^3}\)
\(=\left(x+\cfrac{1}{x}\right)^3-3.\cancel{x}.\cfrac{1}{\cancel{x}}\left(x+\cfrac{1}{x}\right)\)
\(=\left(2\sqrt3\right)^3-3.1.2\sqrt3\)
\(=24\sqrt3-6\sqrt3\)
\(=18\sqrt3\)
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