সমাধান করো : \(tan^2\cfrac{\pi}{4}sin\cfrac{\pi}{x}tan\cfrac{\pi}{6}tan^2\cfrac{\pi}{3}=1\cfrac{1}{2}\)
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\(tan^2\cfrac{\pi}{4}sin\cfrac{\pi}{x}tan\cfrac{\pi}{6}tan^2\cfrac{\pi}{3}=1\cfrac{1}{2}\)
বা, \((1)^2 \times sin\cfrac{\pi}{x} \cfrac{1}{\sqrt3} \times (\sqrt3)^2=\cfrac{3}{2}\)
বা, \(sin\cfrac{\pi}{x} \times \cfrac{3}{\sqrt3} =\cfrac{3}{2}\)
বা, \(sin\cfrac{\pi}{x} =\cfrac{3}{2}\times \cfrac{\sqrt3}{3}\)
বা, \(sin\cfrac{\pi}{x} =\cfrac{\sqrt3}{2}=sin \cfrac{\pi}{3}\)
বা, \(x=3\) [Answer]

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