যদি \(sin51° = \cfrac{a}{ \sqrt {a^2 +b^2}}\)হয়, তবে \(tan39°=\) কত?
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\(sin51° = \cfrac{a}{ \sqrt {a^2 +b^2}}\)
বা, \(sin(90° -39°) = \cfrac{a}{ \sqrt {a^2 +b^2}}\)
বা, \(cos39° = \cfrac{a}{ \sqrt {a^2 +b^2}}\)
বা, \(cos^239° = \cfrac{a^2}{a^2 +b^2}\)
বা, \(sec^239° = \cfrac{a^2 +b^2}{a^2}\)
বা, \(sec^239°-1 = \cfrac{a^2 +b^2}{a^2}-1\)
বা, \(tan^239° = \cfrac{\cancel{a^2} +b^2-\cancel{a^2}}{a^2}\)
বা, \(tan39° =\sqrt{\cfrac{b^2}{a^2}}=\cfrac{b}{a}\)
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