\(\alpha+\beta\)=90° হলে দেখাও \(sec^2\alpha+sec ^2 \beta = sec^ 2 \alpha. sec^2\beta\)
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\(sec^2\alpha+sec ^2 \beta\)
\(=\cfrac{1}{\cos^2\alpha}+\cfrac{1}{cos^2\beta}\)
\(=\cfrac{cos^2\beta+\cos^2\alpha}{\cos^2\alpha cos^2\beta}\)
\(=\cfrac{cos^2(90^o-\alpha)+\cos^2\alpha}{\cos^2\alpha cos^2\beta}\)
\(=\cfrac{sin^2\alpha+\cos^2\alpha}{\cos^2\alpha cos^2\beta}\)
\(=\cfrac{1}{\cos^2\alpha cos^2\beta}\)
\(=sec^ 2 \alpha. sec^2\beta\) [ প্রমানিত]


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